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x^2+120x=2025
We move all terms to the left:
x^2+120x-(2025)=0
a = 1; b = 120; c = -2025;
Δ = b2-4ac
Δ = 1202-4·1·(-2025)
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{22500}=150$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-150}{2*1}=\frac{-270}{2} =-135 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+150}{2*1}=\frac{30}{2} =15 $
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